Free Education for Everyone - student campaign in Ireland. Article "Free Education for Everyone" in English Wikipedia has 46.7 points for quality (as of November 1, 2023). The article contains 26 references and 10 sections.
Since the creation of article "Free Education for Everyone", its content was written by 34 registered users of English Wikipedia and edited by 34 registered Wikipedia users in all languages.
The article is cited 7 times in English Wikipedia and cited 7 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | English: #418554 02.2009 |
Global: #676447 02.2009 |
| Best Rank | English: #90858 08.2012 |
Global: #322226 04.2009 |
On 2 July 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: UEFA Euro 2024, UEFA European Championship, Cristiano Ronaldo, Diogo Meireles da Costa, Merih Demiral, 2024 Copa América, Arda Güler, Turkey national association football team, Copa América, Inside Out 2.
In English Wikipedia the most popular articles on that day were: Kalki 2898 AD, UEFA Euro 2024, Project 2025, 2024 Copa América, A Quiet Place: Day One, Deaths in 2024, Jack Draper (tennis), House of the Dragon, Nikki Hiltz, Diogo Costa.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(35.51+21.49+42.86+71.43+62.25)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
